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m
Line 235: Line 235:     
|B -> C/empty =  
 
|B -> C/empty =  
* Do not meet the requirements to go to E.
+
* Fail the LoS check.
 
|B -> E/empty =  
 
|B -> E/empty =  
* Meet one of the following requirements:
+
* Pass the LoS check.
** Fleet contains a CL
  −
** Fleet contains both (F)BB(V) and CVL
      
|D -> E/empty,G = * Active Branching
 
|D -> E/empty,G = * Active Branching
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