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mLine 235:
Line 235: − + − + + +
→E-1
|B -> C/empty =
|B -> C/empty =
* Fail the LoS check.
* Do not meet the requirements to go to E.
|B -> E/empty =
|B -> E/empty =
* Pass the LoS check of 12 Cn1 F33.
* Meet one of the following requirements:
** Fleet contains a CL
** Fleet contains both (F)BB(V) and CVL
|D -> E/empty,G = * Active Branching
|D -> E/empty,G = * Active Branching