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mLine 626:
Line 626: + + + − end − if count == 3 and str ~= nil then − str = str:sub(0,i) .. "<br>" .. str:sub(i+1,#str) − end − if count == 6 and str ~= nil then − str = str:sub(0,i) .. "<br>" .. str:sub(i+1,#str) − end − if count == 9 and str ~= nil then − str = str:sub(0,i) .. "<br>" .. str:sub(i+1,#str)
no edit summary
else
else
count = count + 1
count = count + 1
if count % 3 == 0 and str ~= nil then
str = str:sub(0,i) .. "<br>" .. str:sub(i+1,#str)
end
end
end
end
end
if count == 0 or string.find(string.lower(str),"maelstrom") ~= nil then
if count == 0 or string.find(string.lower(str),"maelstrom") ~= nil then