5,421
edits
Changes
mLine 619:
Line 619: − + Line 628:
Line 628: − + + + + + + +
no edit summary
local i = 0
local i = 0
local count = 0
local count = 0
for j=0, 4 do
for j=0, 2 do
local prev = i
local prev = i
_, i = string.find(str,"]]",i)
_, i = string.find(str,"]]",i)
end
end
end
end
if count % 3 == 0 and str ~= nil then
if count == 3 and str ~= nil then
str = str:sub(0,i) .. "<br>" .. str:sub(i+1,#str)
end
if count == 6 and str ~= nil then
str = str:sub(0,i) .. "<br>" .. str:sub(i+1,#str)
end
if count == 9 and str ~= nil then
str = str:sub(0,i) .. "<br>" .. str:sub(i+1,#str)
str = str:sub(0,i) .. "<br>" .. str:sub(i+1,#str)
end
end