User:Jigaraphale/Sandbox/12

https://docs.google.com/spreadsheets/d/1tEqI13g2LmzR0L8N-I39W6mgmAyc8DxJ-R0_qlEkjlQ/edit?gid=1505561028#gid=1505561028

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Trigger Rate Formula 1 [1]
[math]\displaystyle{ \text{P}_\text{0} = 3.2 - 0.2 \times \text{K} - \text{N}_\text{Generator} }[/math] If [math]\displaystyle{ \text{Luck}_\text{flag} ≥ 1 \text{ & } \text{N}_\text{Generator} ≥ 3 }[/math], then [math]\displaystyle{ \text{P}_\text{0} = 0 }[/math] [math]\displaystyle{ \text{K} = \bigg\lceil \sqrt{ \text{Luck}_\text{flag} } + 0.3 \times \bigstar_\text{base} + 0.5 \times \bigstar_\text{Kai} \bigg\rceil }[/math]
[math]\displaystyle{ \text{N}_\text{Generator} = 1 }[/math]	[math]\displaystyle{ \text{N}_\text{Generator} = 2 }[/math]	[math]\displaystyle{ \text{N}_\text{Generator} ≥ 3 }[/math]
[math]\displaystyle{ \begin{align} \text{P}_\text{1} = 1 - \text{P}_\text{0} \\ \text{P}_\text{2} = 0 \\ \text{P}_\text{3} = 0 \end{align} }[/math]	[math]\displaystyle{ \begin{align} \text{P}_\text{1} = 1 - \text{P}_\text{0} - \text{P}_\text{2} \\ \text{P}_\text{2} = 0.5 \times ( 1 - \text{P}_\text{0} ) \times ( \text{K} + 2 ) \\ \text{P}_\text{3} = 0 \end{align} }[/math]	[math]\displaystyle{ \begin{align} \text{P}_\text{1} = 1 - \text{P}_\text{2} - \text{P}_\text{3} \\ \text{P}_\text{2} = mini ( 0.3 ; 1 - \text{P}_\text{3}) \\ \text{P}_\text{3} = X \times \text{K} + 0.15 \times ( \text{N} - 3 ) \end{align} }[/math] The X coefficient is unclear yet, being about 0.04~0.045.
With [math]\displaystyle{ \text{P}_\text{0}, \text{P}_\text{1}, \text{P}_\text{2}, \text{P}_\text{3} }[/math] the respective rates for the trigger of smokes levels 0 to 3, [math]\displaystyle{ \text{N}_\text{Generator} }[/math] the amount of Smoke Generators (counted twice for the Kai one), [math]\displaystyle{ \text{Luck}_\text{flag} }[/math] the flagship's luck, [math]\displaystyle{ \bigstar_\text{base} }[/math] the total improvement level of the base generators, [math]\displaystyle{ \bigstar_\text{Kai} }[/math] the total improvement level of the Kai generators,

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Trigger Rate Formula 2 [2]
[math]\displaystyle{ \text{N}_\text{Generator} = 1 }[/math]	[math]\displaystyle{ \text{N}_\text{Generator} = 2 }[/math]	[math]\displaystyle{ \text{N}_\text{Generator} ≥ 3 }[/math]
[math]\displaystyle{ \begin{align} \text{Level 1}_\text{Rate %} = ? \\ \text{Level 2}_\text{Rate %} = ? \\ \text{Level 3}_\text{Rate %} = ? \end{align} }[/math]	[math]\displaystyle{ \begin{align} \text{Level 1}_\text{Rate %} = ? \\ \text{Level 2}_\text{Rate %} = 3 \times \bigg\lceil 5 \times \text{N}_\text{Generator} + 1.5 \times \sqrt{ \text{Luck}_\text{flag} } + 0.3 \times \bigstar_\text{base} + 0.5 \times \bigstar_\text{Kai} - 5 \bigg\rceil + 1 \\ \text{Level 3}_\text{Rate %} = ? \end{align} }[/math]	[math]\displaystyle{ \begin{align} \text{Level 1}_\text{Rate %} = 100 - \text{Level 2}_\text{Rate %} - \text{Level 3}_\text{Rate %} \\ \text{Level 2}_\text{Rate %} = 30 \\ \text{Level 3}_\text{Rate %} = 3 \times \bigg\lceil 5 \times \text{N}_\text{Generator} + 1.5 \times \sqrt{ \text{Luck}_\text{flag} } + 0.3 \times \bigstar_\text{base} + 0.5 \times \bigstar_\text{Kai} - 15 \bigg\rceil + 1 \end{align} }[/math] If [math]\displaystyle{ \text{Level 3}_\text{Rate %} ≥ 70 \text{ %} }[/math], then [math]\displaystyle{ \text{Level 2}_\text{Rate %} }[/math] is reduced for the total of the three rates to be at 100 %.
With [math]\displaystyle{ \text{N}_\text{Generator} }[/math] the amount of Smoke Generators (counted twice for the Kai one), [math]\displaystyle{ \text{Luck}_\text{flag} }[/math] the flagship's luck, [math]\displaystyle{ \bigstar_\text{base} }[/math] the total improvement level of the base generators, [math]\displaystyle{ \bigstar_\text{Kai} }[/math] the total improvement level of the Kai generators,